Provided by www.YuvaJobs.com - Paper Technical - C & C++ i2 Technologies      Q1.Convert 0.9375 to binary    a) 0.0111     b) 0.1011     c) 0.1111     d) noneAns. (c) Q2.( 1a00 * 10b )/ 1010 = 100     a) a=0, b=0     b)a=0, b=1     c) noneAns. (b) Q3. In 32 bit memory machine 24 bits for mantissa and 8 bits for exponent. To increase the range of floating point.    a) more than 32 bit is to be there.    b) increase 1 bit for mantissa and decrease 1 bit for exponent    c) increase 1 bit for exponent and decrease one bit for mantissa Q4.In C,  "X ? Y : Z "  is equal to    a) if (X==0) Y ;else Z    b) if (X!=0) Y ;else Z    c) if (X==0) Y ; ZAns. (b) Q5. From the following program           foo()           int foo(int a, int b)            {              if (a&b) return 1;              return 0;            }    a) if either a or b are zero returns always 0    b) if both a & b are non zero returns always 1    c) if both a and b are negative returns 0 Q6. The  following function gives some error. What changes have to be made            void ( int a,int b)                {                    int t; t=a; a=b; b=t;                }    a) define void as int and write return t    b) change everywhere a to *a and b to *b Q7. Which of the following is incorrect        a) if a and b are defined as int arrays then (a==b) can never be true        b) parameters are passed to functions only by values        c) defining functions in nested loops Q8.  include<stdio.h>        void swap(int*,int*);        main()            {                int arr[8]={36,8,97,0,161,164,3,9}                for (int i=0; i<7; i++)                    {                for (int j=i+1; j<8;j++)                if(arr[i]<arr[j]) swap(&arr[i],&arr[j]);                    }            }                void swap(int*x,int*y)            {                int temp; static int cnt=0;                temp= *x;                *x=*y;                *y=temp;                cnt++;            }    What is cnt equal toa) 7 b) 15 c) 1 d) none of these Q9.      int main()                {                    FILE *fp;                    fp=fopen("test.dat","w");                    fprintf(fp,,hello\n");                    fclose(fp);                    fp=fopen ("test.dat","w");                    fprintf (fp, "world");                    fclose(fp);                    return 0;                }If text.dat file is already present after compiling and execution how many bytes does the file occupy ?a) 0 bytes b) 5 bytes c) 11 bytes d) data is insufficient Q10.    f1(int*x,intflag)            int *y;            *y=*x+3;            switch(flag)                {                    case 0:                     *x=*y+1;                    break;                    case 1:                    *x=*y;                    break;                    case 2:                     *x=*y-1;                       break;                }         return(*y)                    main()            {                *x=5;                i=f1(x,0); j=f1(x,1);                printf("%d %d %d ",i,j,*x);            }             What is the output?a) 8 8 8 b) 5 8 8 c) 8 5 8 d) none of these   Provided by www.YuvaJobs.com - Paper Technical - C & C++