Global Placement Papers

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Globaledge Aptitude Reasoning Aptitude Questions And Answers 04 September 2012
GlobalEdge Aptitude Questions and Answers1.If the number 481 * 673 is completely divisible by 9, then the smallest whole number in place of * will be:A.2B.5C.6D.7E.None of theseAnswer:DEx:Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9.Therefore, x = 7.2.3897 x 999 = ?A.3883203B.3893103C.3639403D.3791203E.None of theseAnswer:BOption : BEX:3897 x 999 = 3897 x (1000 - 1)= 3897 x 1000 - 3897 x 1= 3897000 - 3897= 3893103.3.Sakshi can do a piece of work in 20 days.…
Globaledge Placement Paper 31 December 2010
Sample Test Paper Globaledge1)what is big-endian.a) MSB at lower address LSB at higher addressb) LSB at lower address MSB at higher addressc) memory mgmt techniqued) none of the aboveans:a2)what is Little-endian.a) MSB at lower address LSB at higher addressb) LSB at lower address MSB at higher addressc) memory mgmt techniqued) none of the aboveans:b3)8086 hasa)16 bit data bus ,16 bit address busb)16 bit data bus,32 bit address busc)8 bit data bus,16 bit address busd)8 bit data bus,8 bit address…
Globaledge Placement Paper 31 January 2011
GLOBAL EDGE Placement Question Paper1) main(){ int arr[]={ 1,2,3,4 };int *ptr ;;;;ptr++ = arr;printf("%d,%d",ptr[2],arr[2]);return 0;}what is the output :a> compile time error :multiple termination statements for pointerb> lvalue required for ptrc> prints 3 3d> printd 4 3ans b: lvalue required for ptr;2) main(){char s[10];scanf ("%s",s);printf(s);}what is the output if input is abcd :a> prints abcdb> compiler errorc> prints abcd and 6 junk charactersd> printd sans a: prints abcd.3) main(){char c…
Global Edge General - Other
Sample Test Paper  Globaledge 1)what is big-endian.a) MSB at lower address LSB at higher addressb) LSB at lower address MSB at higher addressc) memory mgmt techniqued) none of the aboveans:a2)what is Little-endian.a) MSB at lower address LSB at higher addressb) LSB at lower address MSB at higher addressc) memory mgmt techniqued) none of the aboveans:b3)8086 hasa)16 bit data bus ,16 bit address busb)16 bit data bus,32 bit address busc)8 bit data bus,16 bit address busd)8 bit data bus,8 bit address…
Global Edge Whole Testpaper 1
GLOBAL EDGE  Placement Paper 5 20051)Remove the odd onesa)job scheduler b)long term scheduler c)medium term schedulerd)process term schedulerans:d2) long term scheduler is also known asa)cpu scheduler b)job scheduler c)middle term scheduler d)none of theseans:b3)which one is not in the process statea)ready b)run c)terminated d)none of theseans: d4)Switching the cpu to another process requires saving the state of the old process and loading the saved state is calleda)mode switch b)process switch…
Global Edge General - Other
GLOBAL EDGE  Placement Question Paper 4 20051. Where is the MBR stored?1. maintained by OS2. MBR is in Boot.3 MBR is in First sector of HDD4. None of the above.2. Where is the partition table stored?1. BIOS2. CMOS Setup3. MBR4. stored per partition.3. Where is the boot record stored?1. BIOS2. CMOS Setup3. MBR4. stored per partition.4. How many primary partitons can be created?1. 12. 23. 34. 4ans : 4.5. What is the difference between primary & extended partion?1. Both are same2. Primary…
Global Edge Whole Testpaper
 GLOBAL EDGE Placement Question Paper 2 2005main(){ int arr[]={ 1,2,3,4 };int *ptr ;;;;ptr++ = arr;printf("%d,%d",ptr[2],arr[2]);return 0;}what is the output :a> compile time error :multiple termination statements for pointerb> lvalue required for ptrc> prints 3 3d> printd 4 3ans b: lvalue required for ptr;2>main(){char s[10];scanf ("%s",s);printf(s);}what is the output if input is abcd :a> prints abcdb> compiler errorc> prints abcd and 6 junk charactersd> printd…
Globaledge Paper General - Other - 1 April 2005
GLOBAL EDGE  Placement Question Paper 4 2005 1. Where is the MBR stored?1. maintained by OS2. MBR is in Boot.3 MBR is in First sector of HDD4. None of the above.2. Where is the partition table stored?1. BIOS2. CMOS Setup3. MBR4. stored per partition.3. Where is the boot record stored?1. BIOS2. CMOS Setup3. MBR4. stored per partition.4. How many primary partitons can be created?1. 12. 23. 34. 4ans : 4. 5. What is the difference between primary & extended partion?1. Both are same2. Primary…
Globaledge Paper Whole Testpaper - 1 February 2005
GLOBAL EDGE Placement Question Paper 2 2005 main(){ int arr[]={ 1,2,3,4 };int *ptr ;;;;ptr++ = arr;printf("%d,%d",ptr[2],arr[2]);return 0;}what is the output : a> compile time error :multiple termination statements for pointerb> lvalue required for ptrc> prints 3 3d> printd 4 3 ans b: lvalue required for ptr;   2> main(){char s[10];scanf ("%s",s);printf(s); } what is the output if input is abcd : a> prints abcdb> compiler errorc> prints abcd and 6 junk charactersd>…
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